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Chem 10 Course Notes
Chem 10 Course Notes 9/16/2011
Chem 10 Course Notes 9/20/2011
9/21 Read Section 2.1 Mixtures, solutions and solvent and Section 2.2 Pure substances and impurities. Answer all questions in both chapters. Due tomorrow 9/22.
Chem 10 Course Notes 9/22/2011
9/22 Read Section 1.7 Q1,2 Section 1.8 Q 1,2 Section 1.9 Q 1, 3
Chem 10 Course Notes 9/26/2011
Homework Due Tuesday 10/4 Section 2.1 Atoms, Elements and Compounds Questions 1-6 and Section 2.2 More About Atoms Questions Questions 1-6. Also read Section 2.3 Radioactivity and Isotopes.
Homework Due Tuesday 10/11 Read Sections 2.3 and 2.4 in the book also do all questions from these 2 sections.
Chem 10 Course Note 10/9/2011 Chapter 2
Homework for Wednesday 10/12/2011- Atomic Structure Work Sheet
Chem 10 Course Notes 10/12/2011
Test on atomic structure and electron structure this coming Wednesday , 19th of October. Please read the notes given above on 10/12/2011.
New Notes on Chapter 2 10-23-2011
Homework-Electron Configuration 10-25-2011
Notes on Bohr Model Hydrogen Atom
More Practice on Electron Configuration with Answers
Quiz 1DrB
Quiz 2 for Final
Quiz 3 for Final
Quiz 4DrB
Quiz 5 for Final
Quiz 6 for Final
Please use this example to do your lab report.
Title: Titration of H2C2O4.H2O with NaOH
Aim: Predict from calculation and measure the volume of NaOH needed to neutralize 0.020dm3 of H2C2O4.2H2O.
Introduction:
Materials List:
H2C2O4.2H2O powder
NaOH powder
Phenolphthalein indicator solution
Apparatus List:
0.020dm3 pipette (20ml)
pipette pump
burette, 0.050dm3(50ml)
2beakers, 250ml
Procedures:
1.
2.
Observations:
Data:
NaOH solution: Mass= 0.41grams in 0.100dm3 water solution
C2O4H2.2H2O: Mass=1.26grams in 0.100dm3 water solution
Titration Data |
Titration | Start Volume, dm3 | Finish Volume, dm3 | Volume NaOH Used |
Run1 | 0.00 | 0.042 | 0.042 |
Run 2 | 0.05 | 0.048 | 0.044 |
| | Average Volume | 0.043 |
Data Processing (Use your values below)
Given that we use 0.020dm3 of oxalic acid in the beaker under the burette, what volume do we predict that we will titrate of NaOH? We know the Mrfor NaOH and oxalic acid or H2C2O4.2H2O.
Now the concentration of acid and base are:
Conclusions (How does the volume calculated and measured compare? Are they close or far apart?)